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Complex Analysis and Differential Geometry




                    Notes          We shall see later as the drama  of the term unfolds that this very suggestive  notation is  an
                                   excellent choice. Now, we have in polar form
                                                                      z = re ,
                                                                          i
                                   where r = |z| and  is any argument of z. Observe we have just shown that
                                                                    e  e  = e i(+) .
                                                                     i
                                                                       i
                                   It follows from this that e  e  = 1. Thus,
                                                       i
                                                         –i
                                                                      1  e  i  
                                                                      e  i  
                                   It is easy to see that
                                                           z   re  i  r             ))
                                                                             
                                                           w    se i   s  (cos(   ) isin(  

                                   1.3 Summary

                                       The modulus of a complex number z = x + iy is defined to be the nonnegative real number
                                   
                                          2
                                             2
                                         x   y ,  which is, of course, the length of the vector interpretation of z.
                                       The conjugate  z  of a complex number z = x + iy is defined by  z  = x – iy.
                                   
                                       In other words, the conjugate of the sum is the sum of the conjugates. It is also true that
                                   
                                        zw  z w.  If z = x + iy, then x is called the real part of z, and y is called the imaginary part
                                       of z. These are usually denoted Re z and Im z, respectively. Observe then that z +  z  = 2 Rez
                                       and z –  z  = 2 Imz.
                                       Now, for any two complex numbers z and w consider

                                                                  
                                                    2
                                             |z + w|  = (z   w)(z   w) (z   w)(z  w)
                                                                  
                                                     = zz (wz   wz) ww
                                                         2
                                                     =|z|  2Re(wz) |w| 2
                                                                  
                                                      |z|  + 2|z||w| + |w|  = (|z| + |w|) 2
                                                                         2
                                                         2
                                       In other words,
                                                                |z + w|  |z| + |w|
                                       the so-called triangle inequality. (This inequality is an obvious geometric fact–can you
                                       guess why it is called the triangle inequality?)
                                       We shall see later as the drama of the term unfolds that this very suggestive notation is an
                                   
                                       excellent choice. Now, we have in polar form
                                                                      z = re ,
                                                                          i
                                       where r = |z| and  is any argument of z. Observe we have just shown that

                                                                    e  e  = e i(+) .
                                                                       i
                                                                     i
                                       It follows from this that e  e  = 1. Thus
                                                              –i
                                                            i
                                                                      1  e  i  
                                                                      e i  


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