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Unit 17: Tensor Fields in Curvilinear Coordinates




          This means that all three curves given by vector-functions (3), (4), and (5) are intersected at the  Notes
          point P  as shown on Fig. 17.1.
                0
                                            Figure  17.1















          Arrowheads on these lines indicate the directions in which parameter t increases. Curves (3), (4),
          and (5) are called coordinate lines. They are subdivided into three families. Curves within one
          family do not intersect each other. Curves from different families intersect so that any regular
          point of space is an intersection of exactly three coordinate curves (one per family).
          Coordinate lines taken in whole form a coordinate grid. This is an infinitely dense grid. But
          usually, when drawing, it is represented as a grid with finite density. On Fig. 17.2 the coordinate
          grid of curvilinear coordinates is compared to that of the Cartesian coordinate system.

                                            Figure  17.2












          Indeed, meridians and parallels are coordinate lines of a spherical coordinate system. The parallels
          do not intersect, but the meridians forming one family of coordinate lines do intersect at the
          North and at South Poles. This means that North and South Poles are singular points for spherical
          coordinates.
          Exercise 1.1: Remember the exact definition of spherical coordinates and find all singular points
          for them.

          17.4 Moving Frame of Curvilinear Coordinates

          Let’s consider the three coordinate lines shown on Fig. 17.1 again. And let’s find tangent vectors
          to them at the point P . For this purpose, we should differentiate vector-functions (3), (4), and (5)
                           0
          with respect to the time variable t and then substitute t = 0 into the derivatives:
                                       dR      R
                                    E   dt i  t 0     y i at the point  0 P .   ...(1)
                                     i
                                           
          Now let’s substitute the expansion (1) into (1) and remember (4):

                                        R  3   x j  3  j
                                                 j 
                                   E    i     e   S e . j                       ...(2)
                                          
                                                      i
                                    i
                                        y  j 1 y  i  j 1
                                                    
                                            
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