Page 335 - DMTH402_COMPLEX_ANALYSIS_AND_DIFFERENTIAL_GEOMETRY
P. 335
Complex Analysis and Differential Geometry
Notes to curves, which states that a parametric surface is uniquely determined by its first and second
fundamental form. Partial derivatives with respect to u will be denoted by a subscript i following
i
a comma, unless there is no ambiguity in which case the comma may be omitted.
Proposition 10. Let X : U be a parametric surface. Then the following equations hold:
3
X m ij X k N, ...(15)
ij
ij
m
where,
1
m
2 g mn g ni,j g nj,i g ij,n , ...(16)
ij
are the coordinate representations of its first and second fundamental form.
g
and and k ij
ij
Proof. Clearly, X can be expanded in the basis X , X , N of . We already saw, that the component
3
ij
1
2
m
of X along N is k , hence Equation (15) holds with the coefficients given by
ij
ij
ij
X X n ij g mn .
m
ij
In order to derive (16), we differentiate g = X X, and substitute the above equation to obtain:
i
ij
j
g ij,m n im g n jm g . ...(17)
ni
nj
Now, permute cyclically the indices i, j,m, add the first two equations and subtract the last one:
g ij,m g mi,j g im,i 2 n jm g .
ni
Multiplying by g and dividing by 2 yields (16).
il
The coefficients are called the Christoffel symbols of the second kind. It is important to note
m
5
ij
that the Christofell symbols can be computed from the first fundamental form and its first
derivatives. Furthermore, they are not invariant under reparametrization.
Theorem 6. Let X : U be a parametric surface. Then the following equations hold:
3
n
m
m
n
m ij,l m il,j g mn k k k k jn , ...(18)
il
ln
il
nj
ij
nl
ij
k ij,l k il,j m ij k lm m il k jm 0. ...(19)
Proof. If we differentiate (15), we get:
X m X m k N ij m X m ij X ml k N k N .
ij
m
ij,l
ij
ij,l
l
ijl
l
l
Substituting X from (15) and N from (5), and decomposing into tangential and normal
l
ml
components, we obtain:
m
X A X B N,
m
ijl
ijl
ijl
where:
m
m
n
A m ij,l g mn k k ,
ln
ij
nl
ijl
ij
lm
B k ij,l m ij k .
ijl
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