Page 433 - DMTH404_STATISTICS
P. 433

Unit 31: Hypothesis Testing



                                                                                                  Notes
                       X -  X -  k
                             2
                        1
            or   Z  =              under H .
                   cal    2    2         0
                         s   s
                          1    2
                            +
                         n    n
                          1    2
            In a similar way, we can write the expressions for t  under different situations.
                                                     cal
                   Example 20: A sample of 100 electric bulbs of 'Philips' gave a mean life of 1500 hours
            with a standard deviation of 60 hours. Another sample of 100 electric bulbs of "HMT" gave a
            mean life of 1615 hours with a standard deviation of 80 hours. Can we conclude that the mean
            life of 'HMT' bulbs is greater then that of 'Philips' bulbs by 100 hours?
            Let  X  = 1615, S  = 80, n  = 100,  X  = 1500, S  = 60, n  = 100.
                 1       1     1       2        2     2
            We can write
            H :   £   + 100 against H :   >   + 100
             0  1  2             a  1  2
                           -
                      -
                 1615 1500 100
            Z  =                  = 1.5
             cal       2    2
                     80   60
                         +
                     100  100
            Since Z  < 1.645, we accept H  at 5% and say that the difference in mean life of 'HMT' bulbs and
                  cal               0
            that of 'Philips' bulbs is less than or equal to 100 hours.
            31.2.4 Paired  t - Test

            This test is  used in situations where there is a pairing  of observations  (X , X ),  like  marks
                                                                         1i  2i
            obtained by students of a class in two subjects, performance of the patients before and after the
            administration of a drug, etc. We define d  = X  - X , the difference in the observations for the i
                                             i   1i  2i
            th item.

                                              d -
                                                          2
                              å  d i        å  ( i  d ) 2  å d -  nd  2
                                                          i
                                       s =
            Then, we compute  d =   and  d          =
                                n             n -  1     n - 1
            As before, we can test H  :   =   against H  :      (two tailed test) or H  :   £ (or ³)   against
                               0  1   2       a  1   2                0  1       2
            H  :   > (or <)   (one tailed test).
             a  1        2
                              d     d  n
                                          t
            The test statistic  t =  =   ~ -distribution  with (n - 1) d.f.
                            s d / n  s d
                   Example 21: Eleven students of B.Com. (Hons) were given a test in economic analysis.
            They were imparted a month's special coaching and a second test was held at the end of it. The
            result were as follows :

                   Student  No .   :  1    2   3   4    5   6   7    8   9   10  11
                 Marks    1  Test  : 36 40 36 34 46 32 38 46 40 38 42
                           st
                       in
                 Marks    2nd  Test  : 40 44 40 40 46 40 34 48 38 44 36
                       in
            Do the marks give an evidence that the students have benefited by extra coaching?




                                             LOVELY PROFESSIONAL UNIVERSITY                                  425
   428   429   430   431   432   433   434   435   436   437   438