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Unit 7: General Properties of Solutions of Linear Differential Equations of Order n




          Therefore the general solution is                                                     Notes
                                      y = C.F. + P.I.

                                                      3        3     1
                                             /2
                                            x
                                        = e     c 1  cos  x c 2  sin  x  (2cos2x  3sin2 )
                                                                                   x
                                                     2         2    13
          Self Assessment
          11.  Solve the following differential equations

               (D   D  2)y  sin 2x

                2
               d y   dy
          12.    2  5    6y  sin3x
               dx    dx
          7.5 Summary


              The unit starts with the existence the uniqueness of the solution of nth order differential
               equation.
              Here the  nth order linear differential equation is reduced to  a system of  n  first order
               equations and the method of last unit applied.
              Some of the properties listed, help us in finding the general solution of the equation when
               the coefficients are constant.

          7.6 Keywords


          Complementary functions are the solutions of the nth order differential equation without the
          non-homogeneous term and involves n arbitrary constants.
          Particular Integral (P.I.): It is the solution of non-homogeneous, nth order differential equation
          without having any arbitrary constants.

          7.7 Review Questions

          1.   Solve

                  2
                 d y   dy
               9     18    16y  0
                 dx 2  dx
          2.   Solve

                4
               d y
                    y  0
               dx  4
          3.   Solve
                 4
                     3
                          2
               (D    D    9D    11D   4) y = 0
          4.   Solve
                2
               d y   dy      4x
                    5    6y  e
               dx  2  dx


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