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P. 143

Differential and Integral Equation




                    Notes          Hence the condition (vii) is necessary and sufficient both. In the vector form the equation (i) can
                                   be written as
                                                            
                                                             . A dr = 0
                                   where

                                                                   ˆ   ˆ   ˆ  and
                                                              A  = Pi Q j  Rk
                                                              
                                                             dr  = dxi ˆ  dy j ˆ  dzk ˆ
                                                                                    
                                                                               .
                                   The necessary and sufficient condition then becomes  A  Curve  A  0  i.e.
                                                      P  Q   R

                                                                 = 0
                                                      x   y   z
                                                      P  Q   R

                                   Self Assessment


                                   1.  Show that the differential equation
                                          3
                                        xz dx z dy  2y dz  0
                                       is integrable.
                                   2.  Show that the differential equation
                                        yz (y z )dx zx (z x )dy xy (x y )dz  0

                                       is integrable.

                                   8.3 Methods for Solving the Differential Equations


                                                             Pdx Qdy Rdx = 0                               ...(1)
                                   The condition for integrability of the above equation is
                                             Q   R      R   P      P   Q
                                          P          Q          R          = 0                             ...(2)
                                             z   y      x    z      y   x

                                   If the differential equation (1) is exact differential then its integral is of the form

                                                 y
                                               x
                                              u ( , , ) = c,                                               ...(3)
                                                   z
                                   Now
                                                          u    u     u
                                                   du =    dx    dy    dz  0                               ...(4)
                                                          x    y     z
                                   Giving us the conditions

                                                                               u      u     u
                                                                         P =     , Q   , R
                                                                               x      y     z




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