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Unit 8: Total Differential Equations, Simultaneous Equations




                                                                                                Notes
                                                P      2 u   2 u  Q
          Now                                      =
                                                y      y x  x y   x
                                                P      Q
          or                                       =
                                                y      x
                                                                                   ...(5)
                                                Q      R  R   P
          Similarly                                =    ,
                                                z      y  x    z
          There are various methods of solving equation (1) which are shown below.

          Method I : Solution by Inspection

          If the conditions of integrability are satisfied, then sometimes by rearranging the terms of the
          given equation and/or by dividing by some suitable function,  the given equation may  be
          changed to a form containing several parts, all of which are exact differential. Then integrating
          it, the integral can be obtained directly.




           Note:  Certain common exact differentials, which may occur in the transformed total differential
          equation are as follows:

                                          xdy ydx = d  (xy )

                                                       (x
                                   xydz xzdy  yzdz = d yz  )
                                         xdy y dx
                                                          x
                                                   = d ( / );
                                                       y
                                            x 2
                                         y dx xdy
                                                          y
                                                       x
                                            y  2   = d ( / )
                                         xdy y dx         1
                                                   = d (tan ( / ))
                                                            y
                                                              x
                                           x 2  y  2
                                         xdx y dy       1    2   2
                                           x 2  y  2  =  d  2 log(x  y  )

                                                z
                                         d f ( , , )
                                              y
                                            x
                                                               z
                                                            x
                                                              y
                                                   = d  log ( , , )
                                                          f
                                             y
                                            x
                                               z
                                          f ( , , )
                                     xdx y dy zdz       1    2   2  2
                                                   = d   log(x  y  z  )
                                       x  2  y  2  z  2  2
                 Example 1: Solve
                     (y  2  yz )dx  (z 2  zx )dy  (y  2  xy )dz = 0                ...(1)



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