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Differential and Integral Equation




                    Notes          Self Assessment

                                   1.  Prove that

                                                     1
                                                   2  2
                                          J  1 ( )x  =  cosx
                                            2      x
                                   Show that when n is any integer positive or negative
                                                    n
                                           J ( x) = ( 1)  J (x)
                                           n          n
                                   The expression for J (x) is given by
                                                   n
                                                       ( 1) s  x  n  2s
                                            J (x) =
                                            n       s !(n s  1)! 2
                                                 s  0
                                   Case I let n be a positive integer. Replacing x     x in the above equation we have


                                                       ( 1) s  x  n  2s
                                           J ( x) =
                                           n        s !(n s  1)!  2
                                                 s  0
                                                       s
                                                    ( 1) ( 1) n  2s  x  n  2s
                                                =
                                                    s !(n s  1)! 2
                                                 s  0
                                                            s
                                                        ( 1) ( 1) 2s  x  n  2s
                                                    n
                                                = ( 1)
                                                        s !(n s  1)! 2
                                                      s  0
                                                    n
                                                        x
                                                = ( 1) J n ( )  as ( 1)  2s  1
                                                    n
                                   Thus    J ( x) = ( 1)  J (x)
                                           n          n
                                   1.4 Recurrence Formulas for J (x)
                                                                    n

                                   Some of the recurrence relations involving Bessel functions are as follows:
                                   I.  x J (x) = n J (x)  x J  (x),
                                         n       n     n + 1
                                               d
                                   where J (x) =   J (x)
                                         n    dx  n
                                   To prove the above relation, we start from the series expansion of J (x) as follows:
                                                                                         n
                                                     ( 1) s  x  n  2s
                                            J (x) =
                                            n       s !(n s )! 2
                                                 s  0
                                   Differentiating it w.r.t. x and multiplying by x on both sides, we have

                                                       s
                                                            s
                                                    ( 1) (n  2 ) x n  2s
                                          x J (x) =          n  2s
                                            n         s !(n s )! 2
                                                 s  0




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