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Unit 22: Solution of Laplace Differential Equation




          Now using (xiv), we get                                                               Notes

                                                    n  b   n
                                                                  x
                                 V ( , ) =   C  n  sin h  sin  x  f ( )
                                     b
                                   x
                                           n  1      a     a
                                             a
                                   n b     2        n  x
                                               x
              or                           C  sin h  =  f ( ) sin  dx
                              n
                                    a      a          a
                                             b
                                                    a
                                               2            n x
              or                                              C n  =  n  b  f  ( )sin  dx  ...(xvi)
                                                       x
                                           a sinh   0        a
                                                 a
          Hence (xv) with coefficient (xvi) in the solution of (i) satisfying the given boundary conditions.
          Case III: Let there be a rectangular plate of length a and width b, the sides of which are kept at
          temperature zero, the lower end is kept at temperature f(x) and the upper edge is kept insulated.
          Boundary conditions are:

                                 V (0, ) = 0                                     ...(xvii)
                                     y
                                     y
                                 V ( , ) = 0                                    ...(xviii)
                                   a
                                 V ( ,0) =  f ( )                                 ...(xix)
                                   x
                                             x
                                  V
                                        = 0                                       ...(xx)
                                  y
                                    Y b
                                            Figure 22.7














          Proceeding as  in  Case  I, assuming  the solution  of  equation  (i) as  V ( , ) X ( ) ( )  and
                                                                               Y
                                                                      x
                                                                             x
                                                                                 y
                                                                       y
          substituting this in equation (i) itself. We get two differential equations.
                                                 2
                               2                 Y
                                X   2 X  = 0 and      2 Y  0
                                x 2              y 2
          whose general solutions are
                                      X = A cos x B  sin x

            and                                                  Y = C  cos h y D  sinh y





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