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Research Methodology




                    Notes          Think for a moment about the qualitative nature of the time variable. It is expressed in years in
                                   this case but could be quarters, months, days, hours, minutes or any other time measurement
                                   unit. How does it differ from advertising expenditures, the independent variable that we examine
                                   in the preceding section? Is there a difference in the effect that a unit of each has on the dependent
                                   variable, or,   1 million in one case and 1 year in the other? Time, as you can readily see is
                                   constant. One year has the same effects as any other. This is not true for advertising expenditures,
                                   especially when you leave the linear environment and enter the nonlinear environments. Then
                                   there may be qualitative difference in the sales impact as advertising expenditures are increased
                                   or decreased by unit.
                                   The worksheet is in Table 10.1 and calculations are as follows:

                                                                Table  10.1:  Worksheet

                                      YEAR      Code for    YEAR     Code for   Divident     XY         X
                                                                                                         2
                                                an Even               an Odd    payments
                                                Series X              Series X   in Rs Y
                                    1990       -9
                                    1991       -7         1991       -4            2.2    -8.8       16
                                    1992       -5         1992       -3            2.4    -7.2        9
                                    1993       -3         1993       -2            3.0    -6.0        4
                                    1994       -1         1994       -1            5.0    -5.0         1
                                    1995       1          1995        0            6.8     0           0
                                    1996       3          1996        1            8.1     8.1         1
                                    1997       5          1997         2           9.0    18.0         4
                                    1998       7          1998        3            9.5     28.5        9
                                    1999       9          1999        4            9.9     39.6        16
                                    Total      0                     0            55.9    67.2         60

                                   Since time is constant in its effect, we may code the variable rather than to use the actual years or
                                   other time units x values. This code assigns a 1 to the first time period in the series and continues
                                   in unit distances to the nth period. Do not start with a zero as this may cause some computer
                                   programs to reject the input. The code is based on the fact that the unit periods are constant, and
                                   therefore their sum may be set equal to zero. See what effect this has on the normal equations for
                                   the straight line.

                                                                   y  = na + bx
                                                                  xy = ax + bx 2
                                   If x = 0, the equations reduce to
                                                y = na

                                               xy = bx 2
                                   which allow the direct solution for a and b as follows
                                                    S y
                                                 a =
                                                     n
                                                    S xy
                                                 b =
                                                    S x  2




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