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Basic Mathematics – I




                    Notes
                                                            1
                                       The critical points are  x   and x = 1
                                                            3
                                                                                 dy
                                       These points divide x-axis into intervals on which    is either positive or negaitve.
                                                                                 dx

                                                                   1          1
                                                                   3

                                                1     1 dy     1     1     3
                                       When  x   ,  say  ,  3     4     1     0
                                                3     4 dx     16    4    16
                                                1    2 dy     4    2      1
                                       When  x    say  ,   3     4    1      0
                                                3    3 dx     4    3      3
                                                    4 dy     16    4
                                       When x > 1 say  ,  3      4    1 1 0
                                                    3 dx      9    3
                                             dy                                 1
                                       Since    changes from positive to neative at  x  ,  the function has a local maxima at
                                             dx                                 3
                                           1
                                        x   .
                                           3
                                       Similarly function has a minima at x = 1

                                   (b)  W e can w rite y = x  – x 2/3
                                                      5/3
                                                             dy    5  2  2  1   1  1        5x  2
                                                                =   x  3  x  3  =  x  3  5x  2
                                                             dx    3     3      3           3x 1 3

                                        dy        2
                                            0  at  x   and uindefined at x = 0. These are two critical points.
                                        dx        5
                                                                   0          2
                                                                              5

                                                          dy   7
                                       When x < 0, say x = –1,    0
                                                          dx    3
                                                  2        1 dy    1
                                       When  0  x    say  x  ,          0
                                                  5        5 dx    1  1 3
                                                                3
                                                                   5
                                                2       3 dy    1
                                       When  x    say  x  ,          0
                                                5       5 dx    3  1 3
                                                              3
                                                                5
                                                                                                            2
                                   Thus there is local maxima (of the type given in Figure 13.2(b)) at x = 0 and minima at  x  .
                                                                                                            5


                                                                                                        x
                                                                                            x
                                          1. If the function f(x) is continuous at the point x = a, and lim f  ( )  and  lim f  ( )  are
                                     Notes                                             x  a –     x  a
                                            both infinite with opposite signs, then the graph of f(x) has a cusp at x = a. Note
                                            that the graph of the function given in example 1(b) above, has a cusp at x = 0.
                                                               x
                                          2. If  lim f  ( )  and  lim f  ( )  are both infinite with same signs, then the graph of f(x)
                                                    x
                                              x  a –      x  a
                                                                                   1
                                            has a vertical tangent at x = a. Note that  ( )f x  x  has a vertical tangent at x = 0.
                                                                                   3
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