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Unit 8: Skewness and Kurtosis: Karl Pearson, Bowley, Kelly's Methods


                •    Coefficient of Skewness in Individual Observations                              Notes
            Example 1:  Calculate the co-efficient of skewness of the following data by using Karl Pearson’s
                        method.
                  Marks:        2            4            4            6            7

            Solution  :

                        Marks (X)             x = (X – A)                  x 2
                                                 A = 4

                           2                      –  2                      4
                           4                      0                         0
                           4                      0                         0
                           6                      2                         4
                           7                      3                         9
                                                                           2
                        ∑ X  = 23                                        ∑ x  = 17

                                             ∑ X   23
                                        X
                                  Mean () =      =    = 4.6
                                              N    5
                        As 4 is repeated twice therefore mode = 4.

                                              ∑ x 2   17
                                        σ
                        Now        S.D.  () =      =      =  3.40  = 1.844
                                               N       5
                                                                  −
                                                     X–Mode    4.6 4    0.6
                                                S
                        Thus, co-efficient of skewness  k  =    =     =      = 0.325
                                                        σ       1.844  1.844
                •    Co-efficient of Skewness in Continuous Series
            Example 2:  Find out the coefficient of skewness for the following distribution:
                    Class:        0–10        10–20      20–30        30–40      40–50

                  Frequency:       14          23          27          21          15

            Solution:

                 Class    Frequency    Mid-value   Deviation        fd           fd 2

                  (x)         (f)         (m)      d = (m – A)
                                                     A = 25

                 0–10         14           5         – 20         – 280         5,600
                 10–20        23           15        – 10         – 230         2,300
                 20–30        27           25           0            0             0
                 30–40        21           35        + 10         + 210         2,100
                 40–50        15           45        + 20         + 300         6,000

                                                                                2
                           ∑  f  = 100                            ∑  fd  = 0  ∑  fd  = 16000





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