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Statistical Methods in Economics


                   Notes                                              ∑  fd
                                                               X =  A +    =  25 +  0    = 25
                                                                       ∑  f     100
                                              Mode (Z) is located in the class interval 20–30.
                                                                         f −  f             27 23
                                                                                              −
                                                                   l +   1   0    i ×   =  20 +     ×  10
                                                               Z=  1
                                                                      2 f −  1  f −  0  f 2  227 −  23 21
                                                                                                 −
                                                                                          ×
                                                                       4
                                                                 =   20 +  ×  10   = 20 + 4 = 24
                                                                       10
                                                                     ∑  fd 2  ⎛  ∑  fd ⎞  2  16000  ⎛  0 ⎞  2
                                                               σ =       −  ⎜  ⎟   =      − ⎜  ⎟
                                                                      N    ⎝  N ⎠     100  ⎝  100 ⎠

                                                                 =  160  = 12.65 Approx.
                                                                             −
                                                                   X – Z   25 24     1
                                               Coefficient of Skewness =    =     =      = 0.08
                                                                     σ     12.65   12.65
                                  Example 3:  The Karl Pearsons coefficient of skewness of a distribution is 0.32. The Standard
                                              Deviation is 6.5 and Mean is 29.6. Find mode.
                                  Solution:   Given           S k  = 0.32,  X  = 29.6, σ  = 6.5, Z = ?

                                                                   X – Z
                                              As we know      S k =   σ

                                              Substituting the values, we get
                                                                       −
                                                                   29.6 Z
                                                             0.32 =   6.5
                                              ⇒           29.6 – Z = 6.5 × 0.32
                                              ⇒                Z = 29.6 – 2.08 = 27.52
                                  (2)  Bowley’s Method
                                      This method is called Second Measure of Skewness, which is propounded by Dr. A.L. Bowley.
                                      This method is based on relative positions of the median and the two quartiles. In a symmetrical
                                      distribution, the upper and lower quartiles are equidistant from median i.e.,
                                                               (M–Q )          (Q –M)
                                                                   1
                                                                                2
                                                            Q 1          M           Q 3

                                      Mathematically,
                                                                     −
                                                          Q − M =  MQ  or  Q +  Q  = M + M or  Q +  3  Q −  1  2M  = 0
                                                                              3
                                                                                  1
                                                                        1
                                                            3
                                      Thus, here skewness is absent.
                                      But in an asymmetrical distribution first and third quartiles are not equidistant from median,
                                      i.e.,
                                                                          Q +  3  Q −  1  2M ≠  0







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