Page 176 - DECO504_STATISTICAL_METHODS_IN_ECONOMICS_ENGLISH
P. 176

Statistical Methods in Economics


                   Notes                      (II and III)

                                                           ∑D 2  = 214, N = 10

                                                                     6 × 214    1284
                                                                =  1 −  3   =  −1    = 1 – 1.297 = – 0.297.
                                                                    10  − 10     990
                                                                                          rd
                                              Rank correlation between the judgments of the 1  and 3  Judge:
                                                                                     st
                                                                     6D  2
                                                                      ∑
                                                              R=  −1
                                                                    N 3  − N
                                              (I and III)
                                                           ∑D 2  = 60, N = 10

                                                                     660        360
                                                                       ×
                                                                =  1 −      =  −1    = 1 – .364 = + 0.636
                                                                    10 3  − 10  990
                                              Thus we find the first and third judges have the nearest approach to common tastes
                                              in beauty.
                                  B.  Where Ranks are not Given ?
                                      When we are given the actual data and not the ranks, it will be necessary to assign the ranks.
                                      Ranks can be assigned by taking either the highest value as 1 or the lowest value as 1. But
                                      whether we start with the lowest value or the highest value we must follow the same method in
                                      case of both the variables.
                                  Example 3: (a)  Calculate Spearman’s coefficient of rank correlation for the following data:
                                       X :          53      98      95      81      75      61      59      55

                                       Y :          47      25      32      37      30      40      39      45

                                  Solution:
                                                       Calculation of Rank Correlation Coefficient

                                          X             R              Y              R           (R  – R )  D 2
                                                                                                         2
                                                         1                              2           1   2
                                          53            1              47              8              49
                                          98            8              25              1              49
                                          95            7              32              3              16
                                          81            6              37              4               4
                                          75            5              30              2               9
                                          61            4              40              6               4
                                          59            3              39              5               4
                                          55            2              45              7              25

                                                                                                  ∑D 2   = 160


                                                                      ∑
                                                                     6D  2
                                                              R=  −1       ;  ∑D  = 160, N = 8
                                                                               2
                                                                    N 3  − N
                                                                      ×
                                                                     6160      960
                                                              R=  1 −  3   =  −1    = 1 – 1.905 = – 0.905.
                                                                     8  − 8    504

         170                              LOVELY PROFESSIONAL UNIVERSITY
   171   172   173   174   175   176   177   178   179   180   181