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Statistical Methods in Economics


                   Notes          Example 4: Find the arithmetic mean of the following data using step deviation method:

                                       X       1590    1610     1630    1650     1670     1690    1710     1730
                                        f       1        2       9       48      131      102      40       17

                                  Solution:

                                        X        f          dx = (X – A)     Step deviation dx’     – fdx’
                                       1590      1       1590 – 1670 = – 80        – 8            1 × – 8 = – 8
                                       1610      2       1610 – 1670 = – 60        – 6            2 × – 6 = – 12
                                       1630      9       1630 – 1670 = – 40        – 4            9 × – 4 = – 36
                                       1650     48       1650 – 1670 = – 20        – 2           48 × – 2 = – 96
                                       1670    131       1670 – 1670 = 00           0            0 × 131 = 0
                                       1690    102       1690 – 1670 = 20           2            102 × 2 = 204
                                       1710     40       1710 – 1670 = 40           4             40 × 4 = 160
                                       1730     17       1730 – 1670 = 60           6             17 × 6 = 102

                                                     ∑ f  = 350                                   ∑ fdx ' = 314
                                              Let assumed mean  A = 1670.
                                                                          dx
                                                                i = 10 dx’ =
                                                                          i
                                                                      ∑ fdx '
                                                               x =   A  +  ∑ f  ×  i
                                                                           '
                                                               A = 1670, ∑ fdx  = 314; ∑ f  = 350; i = 10.
                                                                        314
                                              ∴                x =  1670  +  350  ×  10
                                                                 = 1670 + 8.97
                                              ∴                x = 1678.97
                                  Answer:   The arithmetic mean of the above series is = 1678.97.
                                  Calculation of the Arithmetic Mean in a Continuous Series

                                  The continuous series expresse the data which is very vast. The calculation of arithmetic mean of this
                                  series is similar to that of discrete series after calculating the mid point of each segment of the
                                  continuous series which is called the class interval. The continuous series may have three types of
                                  class intervals: (1) Exclusive class interval for example, 10—20, 20—30, 30—40 .... etc. (2) Inclusive
                                  class interval for example, 0—9, 10—19, 20—29, 30—39 ... etc. If the data is given in the form of
                                  inclusive class intervals, it is first converted into exclusive class interval, (3) Cumulative class interval
                                  for example, more than 10, more than 20 ... etc. or less than 10, less than 20 ... etc.
                                  Example 5: For the following data calculate the mean marks obtained by the students using: (i)
                                              Short-cut method, (ii) Step deviation method.
                                           Marks            10—20     20—30      30—40      40—50      50—60

                                      Number of Students      1         2          3           5         7
                                           Marks            60—70     70—80      80—90      90—100
                                      Number of Students      12        16         10          4




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