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bdkbZ—11% dksfV lglaca/ fof/




            gy (Solution):                                                                            uksV
                           fLi;jeSu dksfV&vUrj fof/ }kjk lglEcU/ xq.kkad dh x.kuk

               Js.kh X       dksfV       Js.kh Y       dksfV    dksfV;ksa dk vUrj
              (X-Series)    (Rank)      (Y-Series)    (Rank)      (Difference       D 2
                              R x                       R y       of Ranks) D
                   22          8              30        9              – 1              1
                   24          6              38        5              + 1              1
                   27          3              40        3               0               0
                   35          1              50        1               0               0
                   21          9              38        5              + 4             16
                   20         10              25        10              0               0
                   27          3              38        5              – 2              4
                   25          5              36        7              – 2              4
                   27          3              41        2              + 1              1
                   23          7              32        8              – 1              1
                                                                                     2
               N = 10                     N = 10                                  ΣD  = 28
                                              L      1             1          O
                                            6 ΣD +  M N  2  1 e  2  −  m 1j  + m  m 2 e  3  −  m 2 P j Q
                                      r  = 1 –       12            12
                                       s
                                                              2
                                                          N(N − 1)
                                               L     1          1        O
                                             628 +  M N  12  3 −  3  3 + (  )  12  ( 3 −  3  3) P Q
                                         = 1 –
                                                       10 10 −(  2  1)

                                               L     1          1         O
                                             628 +  M N  27 3 + (  −  )  ( 27 3) P Q
                                                                      −
                                         = 1 –      12          12
                                                         (
                                                       10 100 1)
                                                             −
                                              (
                                             628 +  2 +  2)
                                         = 1 –
                                                  (
                                                10 99)
                                               (
                                              632)      192    798
                                         = 1 =      = 1 –    =      = + .81
                                              990       990    990
            mPp ifj.kke dk /ukRed lglEcU/A
            mnkgj.k (Illustration) 5: r  dk eku crkvksμ
                                 s
            X      :       15       14        25        14       14        20       22
            Y      :       25       12        18        25       40        10        7














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