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bdkbZ—11% dksfV lglaca/ fof/




                                                                                                      uksV


                   laxkeh fopyu jhfr lg&lEcU/ Kkr djus dh lcls ljy jhfr gSA bl jhfr esa izR;sd ewY; dh
                   mlls fiNys ewY; ls rqyuk dh tkrh gSA

            fof/μ
              (i)  X  vkSj Y Js.kh esa vyx&vyx izR;sd ewY; dh rqyuk mlls fiNys ewY; ls dh tk;sxhA ;fn ewY; fiNys
                  ewY; ls vf/d gS rks mldk fopyu + gksxk] ;fn de gks rks (–) vkSj ;fn leku gS rks (=)A ysfdu ;g
                  è;ku j[kus ;ksX; ckr gS fd fpÉksa dks yxkuk pkfg, mldh ek=kk dks ughaA fopyuksa&;qXeksa dh la[;k oqQy
                  in&;qXeksa dh la[;k ls ,d de gksxh n = (N – 1) D;ksafd igys in dk fopyu ugha gksrkA
             (ii)  X  vkSj Y osQ rRlEoknh fopyu&fpÉksa dk xq.kk djosQ /ukRed xq.kuiQyksa dks fxu fy;k tk;sxk ftls
                  c dgk tk;sxkA
             (iii)  bl lw=k dk iz;ksx fd;k tk;sxkμ
                                               ±   − 2c  n
                                         r  =  ±  n
                                         c

            mnkgj.k (Illustration) 6: fuEu leadksa ls laxkeh fopyu jhfr }kjk lg&lEcU/ xq.kkad Kkr dhft,μ
             S.N.  :   1     2     3     4     5     6     7     8     9     10    11    12
               X   :   89    85    98   102   100   105    96    68    85    98    76    76
               Y   :   32    33    35    37    39    41    40    38    42    40    36    35
            gy (Solution):
                                      laxkeh fopyu&xq.kkad dh x.kuk

                   X            fpÉ          Y            fpÉ          fpÉksa dk xq.kuiQy

                  89                        32
                  85             –          33             +                   –
                  98             +          35             +                  +
                 102             +          37             +                  +
                 100             –          39             +                   –
                 105             +          41             +                  +
                  96             –          40             –                  +
                  68             –          38             –                  +
                  85             +          42             +                  +
                  98             +          40             –                   –
                  76             –          36             –                  +
                  75             –          35             –                  +
                                                                             c = 8

                                       n = N – 1 = 12 – 1 = 11
                                              (2c  − )
                                                   n
                                      r  =  ++   n
                                       c
                                                 ×(2  − 8 11 )  5
                                      r  =  ++    11     =  11  =  .4545
                                       c
                                      r  = .674
                                       c


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