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bdkbZ—11% dksfV lglaca/ fof/
uksV
laxkeh fopyu jhfr lg&lEcU/ Kkr djus dh lcls ljy jhfr gSA bl jhfr esa izR;sd ewY; dh
mlls fiNys ewY; ls rqyuk dh tkrh gSA
fof/μ
(i) X vkSj Y Js.kh esa vyx&vyx izR;sd ewY; dh rqyuk mlls fiNys ewY; ls dh tk;sxhA ;fn ewY; fiNys
ewY; ls vf/d gS rks mldk fopyu + gksxk] ;fn de gks rks (–) vkSj ;fn leku gS rks (=)A ysfdu ;g
è;ku j[kus ;ksX; ckr gS fd fpÉksa dks yxkuk pkfg, mldh ek=kk dks ughaA fopyuksa&;qXeksa dh la[;k oqQy
in&;qXeksa dh la[;k ls ,d de gksxh n = (N – 1) D;ksafd igys in dk fopyu ugha gksrkA
(ii) X vkSj Y osQ rRlEoknh fopyu&fpÉksa dk xq.kk djosQ /ukRed xq.kuiQyksa dks fxu fy;k tk;sxk ftls
c dgk tk;sxkA
(iii) bl lw=k dk iz;ksx fd;k tk;sxkμ
± − 2c n
r = ± n
c
mnkgj.k (Illustration) 6: fuEu leadksa ls laxkeh fopyu jhfr }kjk lg&lEcU/ xq.kkad Kkr dhft,μ
S.N. : 1 2 3 4 5 6 7 8 9 10 11 12
X : 89 85 98 102 100 105 96 68 85 98 76 76
Y : 32 33 35 37 39 41 40 38 42 40 36 35
gy (Solution):
laxkeh fopyu&xq.kkad dh x.kuk
X fpÉ Y fpÉ fpÉksa dk xq.kuiQy
89 32
85 – 33 + –
98 + 35 + +
102 + 37 + +
100 – 39 + –
105 + 41 + +
96 – 40 – +
68 – 38 – +
85 + 42 + +
98 + 40 – –
76 – 36 – +
75 – 35 – +
c = 8
n = N – 1 = 12 – 1 = 11
(2c − )
n
r = ++ n
c
×(2 − 8 11 ) 5
r = ++ 11 = 11 = .4545
c
r = .674
c
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