Page 107 - DMTH402_COMPLEX_ANALYSIS_AND_DIFFERENTIAL_GEOMETRY
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Complex Analysis and Differential Geometry




                    Notes          Every point on the negative real axis and the origin is a singular point of Log z, but there are no
                                   isolated singular points.
                                   Suppose now that z  is an isolated singular point of f . Then there is a Laurent series
                                                  0
                                                                       
                                                                            
                                                                 f(z)    c (z z ) j
                                                                              0
                                                                          j
                                                                      j – 
                                   valid for 0 < |z – z | < R, for some positive R. The coefficient c  of (z – z )  is called the residue
                                                                                             –1
                                                                                            0
                                                                                     –1
                                                  0
                                   of f at z , and is frequently written
                                         0
                                                                      Res f.
                                                                       z  0 z
                                   Now, why do we care enough about c  to give it a special name? Well, observe that if C is any
                                                                 –1
                                   positively oriented simple closed curve in 0 < |z – z | < R and which contains z  inside, then
                                                                                                   0
                                                                            0
                                                                       1
                                                                  c      f(z)dz.
                                                                    1  2 i  C
                                                                       
                                   This provides the key to evaluating many complex integrals.
                                          Example:
                                   We shall evaluate the integral

                                                                       f 1/z dz
                                                                      C
                                   where C is the circle |z| = 1 with the usual positive orientation. Observe that the integrand has
                                   an isolated singularity at z = 0. We know then that the value of the integral is simply 2i times
                                   the residue of e  at 0. Let’s find the Laurent series about 0. We already know that
                                               1/z
                                                                          1
                                                                     z
                                                                    e     z j
                                                                        j 0 z!
                                                                        
                                   for all z. Thus,
                                                                    1     1   1 1
                                                                         1
                                                            e 1/z     z       ...
                                                                      j 
                                                                 j 0 j!    z  2! z 2
                                                                  
                                   The residue c  = 1, and so the value of the integral is simply 2i.
                                             –1
                                   Now suppose, we have a function f which is analytic everywhere except for isolated singularities,
                                   and let C be a simple closed curve (positively oriented) on which f is analytic. Then there will be
                                   only  a finite  number of  singularities of  f inside  C (why?).  Call them  z , z , ...,  z .  For  each
                                                                                              1
                                                                                                      n
                                                                                                 2
                                   k = 1, 2, ..., n, let C  be a positively oriented circle centered at z  and with radius small enough to
                                                 k
                                                                                    k
                                   insure that it is inside C and has no other singular points inside it.











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