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Unit 21: New Spherical Indicatrices and their Characterizations
In order to determine the Bishop frame of the curve = (s), let us form Notes
s b bs
(s) = 2 ds 2 .
0 c c
Since, we can write the transformation matrix
1 0 0
T bs bs T
cos 2 sin 2
N
0 c c M 1 ,
bs bs M
B
sin cos 2
2
0 c 2 c
by the method of Cramer, one can obtain the Bishop trihedra as follows:
The tangent:
1 s s
T ( asin ,acos ,b) (13)
c c c
The M :
1
s bs b s bs b s bs s bs a bs
M = ( cos cos c c 2 c sin sin c 2 , cos sin c 2 sin cos c 2 , c sin c 2 )
c
c
c
c
1
The M :
2
b s bs s bs b s bs s bs a bs
M = ( sin cos c 2 cos sin c 2 , c cos cos c 2 sin sin c 2 , cos c 2 )
c
c
c
c
c
c
2
We may choose a = 12, b = 5 and c = 13 in the equations (1215). Then, one can see the curve at the
Figure 21.1. So, we can illustrate spherical images see Figure 21.2.
Figure 21.1: Circular Helix b = b(s) for a = 12; b = 5 and c = 13
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