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Unit 15: Exponential Distribution and Normal Distribution



                 (i)  The area between the ordinates at m -  and m +  is 0.6826. This implies that for a  Notes
                     normal distribution about 68% of the observations will lie between m -  and m + .
                 (ii)  The area between the ordinates at m - 2 and m + 2 is 0.9544. This implies that for a
                     normal distribution about 95% of the  observations will  lie between  m -  2  and
                     m + 2.

                 (iii)  The area between the ordinates at m - 3 and m + 3 is 0.9974. This implies that for a
                     normal distribution about 99% of the  observations will  lie between  m -  3  and
                     m + 3. This result shows that, practically, the range of the distribution is 6s although,
                     theoretically, the range is from - ¥ to ¥.

            15.3.5 Probability of Normal Variate in an interval

            Let X be a normal variate distributed with mean  m and standard deviation  , also written in
            abbreviated form as X – N(m, ) The probability of X lying in the interval (X , X ) is given by
                                                                         1  2
                                             2
                                         1 X m- ö
                                X 2  1  - ç æ  ÷
                  P (X £  X £  X 2 ò   e  2 è   ø  dX
                             ) =
                     1
                                X 1   2p
            In terms of figure, this probability is equal to the area under the normal curve between the
            ordinates at X = X  and X = X respectively.
                          1        2
                                              Figure  15.4















               Note    It may be recalled that the probability that a continuous random variable takes
              a particular value is defined to be zero even though the event is not impossible.

            It is obvious from the above that, to find P(X  £ X £ X ), we have to evaluate an integral which
                                                1      2
            might be cumbersome and time consuming task. Fortunately, an alternative procedure is available
                                                                               -
                                                                             X m
            for performing this task. To devise this procedure, we define a new variable  z =  .
                                                                               
                                -
                             æ  X m ö  1
                                         ( ) m-
                            E
                       E
            We note that  ( ) z = ç  ÷  =  [E X  ] 0=
                             è    ø  
                            -
                         æ  X m ö  1           1
            and Var z    ç è    ÷ ø  =   2  Var (X m-  ) =   2  Var ( ) 1.X =
                   ( ) Var=
            Further, from the reproductive property, it follows that the distribution of z is also normal.
            Thus, we conclude that if X is a normal variate with mean  m and standard deviation  s, then
               X m
                 -
            z =      is a normal variate with mean zero and standard deviation unity. Since the parameters
                

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