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P. 102
Unit 5: Differential Equations
Notes
Example 4:
x 2
x
2 log ydx dy 0
y
Here M 2 log y
x
x 2
N
y
M 2x
y y
N 2x
x y
M N
So
y y
x 2
x
Thus 2 logx ydx dy dU ( , ) 0
y
y
U
2 log y
x
x
U x 2
y y
U x 2 log y C
1
Also U x 2 logy C 2
x 2 log y a is the solution where a is a constant.
(C) Integrating Factors
Let us consider the differential equation
,
M , x y dx N x y dy 0 ...(i)
whose equation can be put into the form
U , x y a ...(ii)
where a is a constant, now from (ii)
U U
dU , x y dx dy ...(iii)
x y
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