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Differential and Integral Equation




                    Notes                                                 F
                                                       sin   F n =   sin 2  n
                                                                           x

                                                                             F
                                                      sin   F n  =      sin  2  n
                                                                              x
                                                                                       2
                                                                              F n   3 d F n
                                                                 =  2 sin cos     sin    2
                                                                              dx       dx
                                   Substituting in equation (D) we have
                                                             2
                                                    F     2 d F
                                      ( n n  1)F n  2cos  n  sin  2  = 0
                                                    x       dx
                                                             2
                                                  dF x    2 d F
                                   or   ( n n  1)F n  2x  (1 x  )  2  = 0
                                                  dx        dx
                                   Rewriting it as:
                                             2
                                          2 d F n   dF n
                                      (1 x  )  2  2x     ( n n  1)F n = 0                                  ...(E)
                                             dx     dx
                                   This equation (E) is known as Legendre’s differential equations. The solution of equation (E) for
                                   positive integer values of n are known as Legendre Polynomial.
                                   Putting Legendre equation in Fuchs form we have

                                         2
                                        d F n  2x  dF n  ( n n  1) F
                                        dx 2  (1 x 2  ) dx  (1 x 2  )  n = 0                               ...(F)

                                                      dF n
                                   Here let coefficients of    and F  be
                                                      dx      n
                                                                       2x
                                                             x
                                                            p ( ) =                                        ..(G)
                                                                     (1 x 2 )
                                                                    ( n n  1)
                                                              x
                                                            q ( ) =     2
                                                                    (1 x  )
                                   At  x  1  and  x  1,  both   ( )p x  and  ( )q x  have poles of the first order. So the points x = 1 and
                                   x =  1 are regular singular points of the Legendre’s equations. Let us investigate the behaviour
                                   of the equation for  x  . For this purpose let us put
                                                                   1
                                                              x =    , F n  y                             ...(H)
                                                                    r

                                                             dy     dy dr   2 dy
                                                                 =         r
                                                             dx     dx dx    dr










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