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Differential and Integral Equation




                    Notes                2
                                        d     2  0.                                                        ...(ix)
                                        d  2

                                         2
                                        d T  2  2
                                             c  T  0.                                                      ...(x)
                                        dt  2
                                   Equation (ix) has the solution of the form

                                           Ae  i                                                           ...(xi)
                                   Substituting new  variable s =  r  in equation (vii), we have

                                         2
                                        d R  1 dR      2
                                                   1     R  0
                                        ds 2  s ds    s  2
                                   which is Bessel s equation whose general solution is
                                        R  C J s  C Y s
                                                   2
                                            1
                                   or   R  C J  r  C Y   r
                                                    2
                                            1
                                   But since the deflection of the membrane is always finite while  Y  becomes infinite as  r  0
                                   hence we cannot use Y  and must choose C  = 0.
                                                                     2
                                   Now using boundary condition (iii)

                                        u a , ,t  R a  T t

                                            R a  0

                                   Otherwise if    0 or T t  0, u  0

                                        R a  GJ    a  0

                                   or   J   a  0                                                          ...(xii)

                                   Let   1 ,  2  be the positive root of (xii),
                                   The corresponding solution of (viii)

                                        T  A n cose  nt  B n sinC  nt
                                   Thus we get the general solution as


                                        u r , ,t     A  n  cosC  n t  B  n  sin  n t e  i  J  n r         ...(xiii)
                                                 1 n  1
                                   which satisfies the boundary condition (iii).
                                   Considering the solution of the wave equation (ii) which are radially symmetric i.e. when the
                                   solution is independent of  , we get the general solution as


                                        u  , r t  A n  cosC  n t B n sinC  n t J 0  n r                   ...(xiv)
                                              n  1





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