Page 173 - DCOM202_COST_ACCOUNTING_I
P. 173

Unit 8: Overheads




               In  such  cases  various  service  departments  have  to  share  overheads  of  each  other.  The   Notes
               methods available for dealing with reciprocal services are
               (i)   Simultaneous equation method;
               (ii)   Repeated distribution method;
               (iii)  Trial and error method.

          Simultaneous Equation Method

          In  this  method,  the  following  algebraic  equations  help  in  finding  out  cost  of  service
          departments.
          Illustration:  A  company  has  three  production  departments  and  two  service  departments.
          Distribution summary of overheads is as follows:
                    Production departments                  Service departments
           A                  ` 3,000            1.                 ` 234
           B                  ` 2,000            2.                 ` 300
           C                  ` 1,000
          The expenses of service departments are charged on a percentage basis which is as follows:
                             A           B            C            1            2
                1.          20%         40%          30%           -           10%
                2.          40%         20%          20%          20%           -
          Find out the total overheads of production departments using the following methods:
          (A)  Simultaneous Equations Method
          (B)   Repeated Distribution Method

          Simultaneous Equations Method – Example
          Let x denotes total overhead of service department 1
                y denotes total overhead of service department 2
          Therefore,     x = 234 + 0.2y                                           …(1)
                         y = 300 + 0.1x                                           …(2)

                         x – 0.2y = 234                                           …(1)
                         – 0.1x +     y = 300                                     …(2)
          To solve the equations, re-arrange these and multiply by 10 to eliminate decimals.
                         10x – 2y = 2,340                                         …(1)
                         – x + 10y = 3,000                                        …(2)

          Multiplying second equation by 10 and adding
                         10x  –     2y = 2,340
                         –10x + 100y = 30,000
                         98y  = 32,340
                         y= 32,340 ÷ 98
                         y = 330
                         x = 300




                                           LOVELY PROFESSIONAL UNIVERSITY                                   167
   168   169   170   171   172   173   174   175   176   177   178