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Real Analysis




                    Notes
                                                            Figure 15.6: Claim 1 (left) and
                                                            Claim 2 (right) visualizations.




                                   15.4 Dini’s Theorem

                                   Now, we are above to state in certain sense a converse to Theorem 1.

                                   Theorem 4: (Dini’s Theorem). Let  { }f  ¥   be a sequence of real-valued functions on  [ , ].a b  If:
                                                                n n=  1
                                   (a) f   f pointwise, (b)  all  f  are continuous, (c)  f is continuous and (d)  x" Î [ , ] : { ( )} ¥ n= 1
                                                                                                   a
                                                                                                           x
                                                                                                     b
                                                                                                         f
                                      n
                                                           n
                                                                                                         n
                                   is monotone then  f   f  uniformly.
                                                   n
                                                0
                                   Proof: Given  e >  we want
                                                                           a
                                                                                      x
                                                                       x
                                                      "e >  0 N Î  " n ³ " Î [ , ] : f  n ( ) -  f  ( ) < e .
                                                           $
                                                                                 x
                                                                            b
                                           b
                                          a
                                   Let  x Î [ , ]. Since  f   f  pointwise
                                                    n
                                                                          x
                                                              x
                                                                               x
                                                           $ N ( ) Î  " n ³  N ( ) : f  n ( ) < e /2.
                                   In particular,
                                                                     x
                                                                          x
                                                                 f  N  ( ) ( ) -  f  ( ) < e /2.
                                                                   x
                                               y
                                                    y
                                   Let  ( )g y =  f  N  ( ) ( )-  f ( ).  Then  ( )g y  is continuous by (b) and (c). In particular  ( )g y  is continuous
                                             x
                                   at x
                                                                             x
                                                                 a
                                                                       -
                                                                   b
                                                            "
                                                                                     -
                                                  $d ( ) >  0 . . y Î [ , ] : y x < d ( ) Þ  g ( ) g ( ) < e /2
                                                          s
                                                                                   y
                                                     x
                                                                                        x
                                                           t
                                   which implies
                                                                 y
                                                                                      x
                                                                            y
                                                                      y
                                                        f N  ( ) ( ) -  f  ( ) =  g ( ) £  g ( ) g ( ) +  g ( ) =
                                                                              -
                                                            y
                                                                                 x
                                                          x
                                                          y
                                                            -
                                                                            x
                                                       =  g ( ) g ( ) +  f  ( )-  f  ( ) < e /2+ e  /2 < e .
                                                                       x
                                                               x
                                                                    N  ( )
                                                                     x
                                   Moreover,
                                                          x
                                                                       -
                                                                                         y
                                                                 a
                                                            "
                                                    " n ³  N ( ) y Î [ , ] : y x < d ( ) Þ  f  ( )-  f  ( ) < e
                                                                   b
                                                                                    y
                                                                             x
                                                                                  n
                                   since, by (d)
                                                                             y
                                                                                  y
                                                              f n ( ) -  f  ( ) £  f N  ( ) ( ) -  f ( ) .
                                                                     y
                                                                y
                                                                           x
                                                                 a
                                                  x
                                   Denote ( ) (I x =  x - d ( ), x+ d ( )) x Î [ , ]. We have shown
                                                            "
                                                         x
                                                                  b
                                                                                    y
                                                      x
                                                                               b
                                                                                         y
                                                                         x
                                                   $ N ( ) Î  " n ³  N ( ) y Î I ( ) Ç  [ , ] : f  ( ) -  f  ( ) < e .
                                                                    "
                                                                             a
                                                                  x
                                                                                   n
                                   Note that,  { ( )}I x  x Î [ , ]  is a cover for  [ , ],a b  since  x"  is covered at least by  ( ).I x  By Heine-Borel
                                                  a
                                                   b
                                   Theorem 3 there is finite subcover  { ( ), ( ),..., (I x 1  I x 2  I x m  )}. Choose  N =  max{ ( ), ..., N x m  )}  for
                                                                                                        (
                                                                                                 x
                                                                                               N
                                                                                                  1
                                                                    I
                                                                     x
                                                             b
                                                                                                            x
                                                            a
                                   any  e >  0.  Let  n ³  N  and  x Î [ , ]. Let  ( )  be an interval converging x. Then  x x-  i  < d ( ).
                                                                      i
                                                                                                             i
                                                          x
                                                                           x
                                                                                x
                                   Since  n ³  N  we have  n ³  N ( )  and therefore  f n ( ) -  f ( ) < e .
                                                           i
                                   Are all conditions of Dini’s Theorem 4 important? The answer is yes, look at following examples.
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