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Unit 8: Total Differential Equations, Simultaneous Equations
Therefore Notes
xdx ydy zdz = 0 ...(2)
x 2 y 2 z 2
or d = 0
2 2 2
or x 2 y 2 z 2 = constant = c ...(3)
1
Similarly
y dx xdy zdz y dx xdy zdz
yz (y x ) xz (x y ) z (x 2 y 2 ) = 0
Thus
ydx xdy zdz = 0
z 2
Thus xy = constant = c ...(4)
2 2
So the two integrals (3), (4) are complete integrals of (1) Q.E.D.
Example 2: Solve
dx dy dz
x 2 y 2 = 2xy (x y )z ...(1)
Solution: From the first two members
dx dy dz
x 2 y 2 2xy = (x y )z
or
dx dy dz
= ...(2)
x y z
Integrating (2) we have
log(x y ) = log z logc
x y = cz ...(3)
Also from (i)
dx dy dx dy
(x y 2 ) = (x y ) 2 ...(4)
Integrating (4) we have
(x y ) 1 = (x y ) 1 c 2 (c being a constant) ...(5)
2
1 1
or = c 2
x y x y
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