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Differential and Integral Equation




                    Notes          Standard I

                                   In this form of the equation only p and q are present. The partial differential equation will be of
                                   the form
                                                           f (p, q) = 0                                    ... (1)

                                   in which x, y, z do not appear. The complete integral is
                                                               z = ax + by + c                             ... (2)
                                   where a and b are connected by the relation
                                                           f (a, b) = 0                                    ... (3)

                                            z           z
                                   Since  p   a  and  q    b , which on substitution becomes the given equation (1).
                                           x            y
                                   To find the general solution, let from (3) put b =  (a) and replacing c by   (a), we have

                                                               z = ax +   (a)y +   (a)                     ... (4)
                                   Differentiating (4) with respect to a,
                                                              0 = x + y  (a) +   (a)                       ... (5)

                                   The general solution is obtained by eliminating a between (4) and (5).
                                   Suppose from (2), b =   (a) and replacing c by  (a) the general solution is obtained by eliminating
                                   ‘a’ between the following equations:

                                                               z = ax +  (a) y +   (a).                    ... (6)
                                   Differentiating (3) with respect to a,
                                                              0 = x + y  (a) +   (a)                       ... (7)
                                   Now to find the singular integral, differentiate
                                                               z = ax +  (a) y + c

                                   with respect to a and c,
                                                              0 = x + y  (a)
                                   and                        0 = 1.

                                   Now the last equation shows that there is no singular integral.
                                   Illustrative Examples



                                          Example 1: Solve: q = exp. (  p/a).
                                   Solution:

                                   The complete integral is
                                          z =  x +  y +
                                   where    = exp. (   /a)
                                   i.e., the complete integral is
                                          z =   x + {exp. (   /a} y +




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