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Differential and Integral Equation




                    Notes
                                                     2    2
                                                                x
                                               =         x  (3y  5 )
                                                 (D  3D  )
                                               = 2 x  2 {3(k  3 ) 5 }dx ,                         where k + 3x = y
                                                           x
                                                               x
                                               = 2 x  2 (3k  14 )dx
                                                           x

                                               = 2kx  3  7x  4  2x  3 (y  3 ) 7x  4
                                                                  x
                                               = x  3 (2y x ).

                                   Self Assessment

                                   11.  Solve

                                              2
                                        (D D  ) z  2cosy x sin y
                                   12.  Solve
                                        (D 2  DD  2D  2 )z  (y  1)e  x


                                   20.6 The Non-homogeneous Equation with Constant Coefficients

                                   The simplest case is

                                         (D mD     )z = 0

                                                                y
                                   or               z = e  (mD  ) a x  ( )
                                   where D  has been considered algebraic and   is arbitrary.

                                                      = e  ax  (y mx ).

                                   Note. Also
                                         (D mD     )z = 0.

                                   or          p mq   =  z.
                                     The subsidiary equations are

                                                  dx     dy  dz
                                                      =        .
                                                   1      m   z

                                                    z = e  x  (y mx ).
                                   Similarly the integral of

                                     (D m D     1  )(D m D  2  )(D m D  3 )... = 0
                                                                  3
                                          1
                                                      2
                                   is   z  e  1 n  1 (y m x ) e  2 n  2 (y m x ) e  3 n  3 (y m x ) ...
                                                    1
                                                                              2
                                                                 2


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