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Unit 7: Mean Deviation and Standard Deviation


            said to be less variable or more consistent, more uniform more stable or more homogeneous. Coefficient  Notes
            of variation is denoted by the symbol C.V. and is obtained as follows:
                                      σ
            Coefficient of variation or C.V. =   × 100 .
                                       X
            It may be pointed out that although any measure of dispersion can be used in conjunction with any
            average in computing relative dispersion, statisticians, in fact, almost always use the standard deviation
            as the measure of dispersion and the arithmetic mean as the average. When the relative dispersion is
            stated in terms of the arithmetic mean and the standard deviation, the resulting percentage is known
            as the coefficient of variation of coefficient of variability.
            A distinction is sometimes made between coefficient of variation and coefficient of standard deviation.
                                                                                      ⎛  σ ⎞
            The former is always a percentage, the latter is just the ratio of standard deviation to mean, i.e., ⎜  ⎟  .
                                                                                      ⎝  X ⎠
            Example 13:  The scores of two batsmen A and B in ten innings during a certain season are:
                  A     32     28     47    63     71     39     10    60     96     14

                  B     19     31     48    53     67     90     10    62     40     80

                        Find (using coefficient of variation) which of the batsmen A, B is more consistent in
                        scoring.                                         (B.Com., Calcutta Univ., 1996)
            Solution:
                                   Calculation of Coefficient of Variation

                 X         (X – 46)         x 2           Y         (Y– γ )         y 2
                              x                                       y
                32          – 14           196           19          – 31          961
                28          – 18           324           31         – 19           361
                47          + 1             1            48          – 2            4
                63         + 17            289           53          + 3            9
                71         + 25            625           67         + 17           289
                39           – 7           49            90         + 40          1600
                10          – 36          1296           10         – 40          1600
                60         + 14            196           62         + 12           144
                96         + 50           2500           40         – 10           100
                14          – 32          1024           80         + 30           900
                                                                                  2
                                          2
              ΣX  = 460    Σx  = 0      Σx  = 6500     ΣY  = 500    Σy  = 0     Σy  = 5968
                                 Batsman A                   Batsman B
                                   σ                           σ
                             C.V. =   × 100              C.V. =   × 100
                                   X                           Y

                                   460                         500
                              X  =   10   = 46             Y  =   10   = 50

                                    Σx 2    6500                 Σ y 2  5968
                              σ =        =       = 25.5    σ =       =       = 24.43
                                     N      10                   N       10




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