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Unit 7: Mean Deviation and Standard Deviation


                        wage and standard deviation of all the workers taken together.               Notes

                 Section        No. of workers        Mean wage         Standard deviation
                                  employed              in Rs.               in Rs.
                    A                 50                 113                   6
                    B                 60                 120                   7
                    C                 90                 115                   8

                                          NX  1 +  N X 2 +  N X 3
                                                  2
            Solution:               X 123 =   1  N +  N +N 3  3
                                                    2
                                               1
                                          (      )50 113  +  (×  )60 120  +  (×  ×  )90 115
                                        =
                                                        +
                                                     + 60 60 90
                                                    +
                                              + 5650 7200 10350  23200
                                        =                  =       Rs. 116.
                                                200          200
                        Combined standard deviation of three series.

                                                          σ
                                              σ
                                           N 11 2  2 2 2 +N 3 3 2 +N d  2 +N d  2  + N d  2
                                                    σ +N
                                                                            3 3
                                                                      2 2
                                                                1 1
                                    σ 123  =
                                                          1  + N  2  + N  N 3
                                      d =  X– X 123  =  113 – 116  = 3
                                            1
                                      1
                                      d 2 =  X– X 123  =  120 – 116  = 4
                                            2
                                      d 3 =  X– X 123  =  115 – 116  = 1
                                            3
                                                2
                                                    ( ) +90 8 +50 3 +60
                                    σ 123 =   50 () 6 +60 7  2  ( ) 2  () 2  ( ) +4  2  90 (—1 ) 2
                                                             + 50 60 90
                                                                 +
                                                     +
                                                          +
                                                              +
                                                                   +
                                               + 1800 2940 5760 450 960 90  12000
                                        =                               =        =  60  = 7.75.
                                                       200                 200
            2.  Standard deviation of n natural numbers: The standard deviation of the first n natural numbers
                can be obtained by the following formula:
                                            1
                                      σ =     (  2  ) N–1
                                           12
                Thus, the standard deviation of natural numbers 1 to 10 will be
                                            1  (  2     1
                                      σ =          ) 10 –1  =   ×99  =  8.25  = 2.872.
                                           12           12
                Note: The answer would be the same when direct method of calculating standard deviation is
                used. But this holds good only for natural numbers from 1 to n in continuation without gaps.
            3.  The sum of the squares of the deviations of items in the series from their arithmetic mean is
                minimum. In other words, the sum of the squares of the deviations of items of any series from
                a value other than the arithmetic mean would always be greater. This is the reason why standard
                deviation is always computed from the arithmetic mean.




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