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Statistical Methods in Economics


                   Notes
                                                                N σ  2  +  N σ  2  +  N d  2  +  N σ  2
                                                        σ 12  =   1 1   22 1  N 1 1   22
                                                                         N +
                                                                               2
                                      where  σ 12  = combined standard deviation;  σ  = standard deviation of first group;  σ  =
                                                                             1
                                                                                                              2
                                      standard deviation of second group;  d  = (  1  1  12 ;  d  = ( ) X– X  2  2  12 .
                                                                                              ) X– X
                                      The above formula can be extended to find out the standard deviation of three or more groups.
                                      For example, combined standard deviation of three groups would be:

                                                                N  σ  2  σ +N  2 +N  σ  2 +N d  2 +N d  2  + N d  2
                                                        σ 123 =   11    2 2   3 3   1 1   2 2    3 3
                                                                              1  + N  2  + N  N 3

                                                          d 1  =  X– X 123 ,  d  =  X– X 123 ,  d  =  X– X 123 .
                                                                               2
                                                                 1
                                                                                              3
                                                                                        3
                                                                         2
                                  Example 11:  The number examined, the mean weight and the standard deviation in each group of
                                              examination by two medical examiners is given below. Find the mean weight and
                                              standard deviation of both the groups taken together.
                                         A                    50                 113                  6.5
                                         B                    60                 120                  8.2

                                                                    NX  1  + N X 2
                                  Solution:                   X 12 =   1 N+N 2 2
                                                                        1
                                                               N 1  = 50,  N  = 60,  X  = 113,  X  = 120
                                                                        2
                                                                                1
                                                                                         2
                                                                    (      )50 113  +  (×  ×  )60 120  5650  + 7200  12850
                                                              X 12  =     50 + 60     =    110    =   110   = 116.82


                                                                      N  σ  2  σ +N  2 +N d  2 +N d  2 +N d  2
                                                              σ 12 =   1 1   2 2  N 1  11  2  11  2 2
                                                                                    + N

                                                               N 1  = 50, σ  = 6.5,  N  = 60, σ  = 8.2
                                                                                        2
                                                                        1
                                                                                3
                                                                d 1 =  X– X 12  = (113 – 116.82) = – 3.82
                                                                      1
                                                                d 2 =  X– X 12  = (120 – 116.82) = 3.18.
                                                                      2
                                              Substituting the values

                                                                           2
                                                                        ( 50  )6.5 +60 (  )8.2  2  ( +50 −  ) 3.82  2  ( +60 3.18 )  2
                                                              σ 12  =
                                                                                      +
                                                                                   50 60
                                                                                        +
                                                                      2112.5      + + 4034.4 729.62 606.744  7483.264
                                                                  =                              =
                                                                                 110                  100
                                                                  =  68.03  = 8.25.
                                  Example 12:  The number of workers employed, the mean wage (in Rs.) per month and the standard
                                              deviation (in Rs.) in each section of a factory are given below. Calculate the mean



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