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VED1
          E\L-LOVELY-H\math15-1 IInd 6-8-11 IIIrd  24-1-12 IVth 21-4-12 Vth 20-8-12 VIth 10-9-12



          vFkZ'kkfL=k;ksa dk xf.kr




                   uksV
                                                               gy lfgr mnkgj.k

                                                  3 cos (log x )
                                      mnkgj.k 1- 	 ∫              dk eku Kkr dhft,A
                                                 1      x

                                            3 cos (log x )
                                      gy %  ∫             eku yks @ ,   - # rks   >   !  - !#
                                            1      x

                                      tc              -  . # - @ ,     - 3
                                vkSj tc               - !. # - @ , !
                                             3 cos (log )x     log 3
                                      ∴     ∫ 1   x      !  - ∫ 0  cos t  !# - [  ]sin t  log3
                                                                                 0
                                                           - 
 
  @ , !  2 
 
  3  - 
 
  @ , !             mÙkj


                                                ∫
                                      mnkgj.k 2-   1  x   	   dk eku Kkr dhft,A
                                                 0
                                                   1+ x 2

                                      gy % eku yks   -   
 θQ  ∴    !  - 
    θ !θ
                                      tc          - 3. rks   
 θ - 3 vFkkZr~ θ - 3
                                                                 1
                                rFkk tc   -  . rks   
 θ -   vFkkZr~ θ -    π
                                                                 4

                                                   x

                                      ∴       ∫ 0 1  1 +  x 2   !  - ∫ 0 π /4  1 +  tan θ 2     
    θ !θ
                                                                      tan θ
                                                           -  ∫ 0 π /4 tan θ    
    θ !θ -  ∫ 0 π  /4 sec θ  tan θ   !θ

                                                                  sec θ
                                                           - [     ]sec θ  π  /4  =  sec  π   2 
   3 -   2   2     mÙkj
                                                                   0        4

                                                ∫  a  x
                                      mnkgj.k 3-   0  a 2  − x 2      dk eku Kkr dhft,A


                                                                                    1
                                      gy % eku yks &  2    - #. rks 2    !  - !# ;k   !  - 2    !#


                                                                                    2



                                vkSj                  tc   - 3. # - &  vkSj tc   - &. # - &  2 &  - 3
                                                   x
                                             ∫ 0 a  a −  x 2   !  - 2  1    ∫  a 0 dt t  =−  1  a 0 2 ∫  t − 1/ 2   !#
                                                                    2
                                                                            2
                                                               2
                                                  2
                                                               1       0
                                                           -2      2t 1/ 2 
                                                               2      a   2


                                                           - 2 03 2  &   1 -  &    - &                      mÙkj
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